LeetCode - LinkedList - Odd Even Linked List

Given a singly linked list, group all odd nodes together followed by the even nodes. Please note here we are talking about the node number and not the value in the nodes.

You should try to do it in place. The program should run in O(1) space complexity and O(nodes) time complexity.

Example 1:

Input: 1->2->3->4->5->NULL
Output: 1->3->5->2->4->NULL

Example 2:

Input: 2->1->3->5->6->4->7->NULL
Output: 2->3->6->7->1->5->4->NULL
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) { val = x; }
 * }
class Solution {
    public ListNode oddEvenList(ListNode head) {
        ListNode temp = head;
        int i=1;
        List<ListNode> oddList = new ArrayList<ListNode>();
        List<ListNode> evenList = new ArrayList<ListNode>();
        while(temp != null){
            temp = temp.next;
        ListNode temp2=head;
        for(int j=1;j<oddList.size();j++){
            temp2.next = oddList.get(j);
            temp2 = temp2.next;
        for(int j=0;j<evenList.size();j++){
            temp2.next = evenList.get(j);
            temp2 = temp2.next;
            if(j == evenList.size()-1) temp2.next = null;
        return head;

Recent Updates

Recent updates on DevOpsPal


Follow us of social for latest updates.

DevOps Hub

Links to get started.